1013334341300 has 72 divisors (see below), whose sum is σ = 2214840532800. Its totient is φ = 402407377920.

The previous prime is 1013334341233. The next prime is 1013334341333. The reversal of 1013334341300 is 31434333101.

It is a self number, because there is not a number n which added to its sum of digits gives 1013334341300.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 15109241 + ... + 15176159.

Almost surely, 2^{1013334341300} is an apocalyptic number.

1013334341300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1013334341300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1107420266400).

1013334341300 is an abundant number, since it is smaller than the sum of its proper divisors (1201506191500).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1013334341300 is a wasteful number, since it uses less digits than its factorization.

1013334341300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 68025 (or 68018 counting only the distinct ones).

The product of its (nonzero) digits is 3888, while the sum is 26.

Adding to 1013334341300 its reverse (31434333101), we get a palindrome (1044768674401).

The spelling of 1013334341300 in words is "one trillion, thirteen billion, three hundred thirty-four million, three hundred forty-one thousand, three hundred".