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102015247 is a prime number
BaseRepresentation
bin1100001010010…
…10000100001111
321002221220121111
412011022010033
5202103441442
614042312451
72346054355
oct605120417
9232856544
10102015247
1152648624
122a1b8727
131819ab69
14d7977d5
158e51b17
hex614a10f

102015247 has 2 divisors, whose sum is σ = 102015248. Its totient is φ = 102015246.

The previous prime is 102015229. The next prime is 102015289. The reversal of 102015247 is 742510201.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (742510201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 102015247 - 215 = 101982479 is a prime.

It is a super-2 number, since 2×1020152472 = 20814221240942018, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (102015547) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51007623 + 51007624.

It is an arithmetic number, because the mean of its divisors is an integer number (51007624).

Almost surely, 2102015247 is an apocalyptic number.

102015247 is a deficient number, since it is larger than the sum of its proper divisors (1).

102015247 is an equidigital number, since it uses as much as digits as its factorization.

102015247 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 560, while the sum is 22.

The square root of 102015247 is about 10100.2597491352. The cubic root of 102015247 is about 467.2561523933.

Adding to 102015247 its reverse (742510201), we get a palindrome (844525448).

The spelling of 102015247 in words is "one hundred two million, fifteen thousand, two hundred forty-seven".