Base | Representation |
---|---|
bin | 11101101101110100011… |
… | …00111011101000010100 |
3 | 10121121110102100010222112 |
4 | 32312322030323220110 |
5 | 113212032441420200 |
6 | 2101015534050152 |
7 | 133524051004505 |
oct | 16667214735024 |
9 | 3547412303875 |
10 | 1021031201300 |
11 | 3640205497a0 |
12 | 145a71349958 |
13 | 7538a4b6356 |
14 | 375bd67cbac |
15 | 1b85ccc8535 |
hex | edba33ba14 |
1021031201300 has 144 divisors (see below), whose sum is σ = 2574947817792. Its totient is φ = 347298969600.
The previous prime is 1021031201299. The next prime is 1021031201371. The reversal of 1021031201300 is 31021301201.
It is a super-2 number, since 2×10210312013002 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2880614 + ... + 3215586.
It is an arithmetic number, because the mean of its divisors is an integer number (17881582068).
Almost surely, 21021031201300 is an apocalyptic number.
1021031201300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1021031201300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1287473908896).
1021031201300 is an abundant number, since it is smaller than the sum of its proper divisors (1553916616492).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1021031201300 is a wasteful number, since it uses less digits than its factorization.
1021031201300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 335178 (or 335171 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 14.
Adding to 1021031201300 its reverse (31021301201), we get a palindrome (1052052502501).
Subtracting from 1021031201300 its reverse (31021301201), we obtain a palindrome (990009900099).
The spelling of 1021031201300 in words is "one trillion, twenty-one billion, thirty-one million, two hundred one thousand, three hundred".
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