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102112012127 is a prime number
BaseRepresentation
bin101111100011001011…
…0011010011101011111
3100202120100202200020002
41133012112122131133
53133111133342002
6114524250444515
710243300532156
oct1370626323537
9322510680202
10102112012127
113a33a629074
121795913373b
139824244c68
144d2975659d
1529c9876002
hex17c659a75f

102112012127 has 2 divisors, whose sum is σ = 102112012128. Its totient is φ = 102112012126.

The previous prime is 102112012069. The next prime is 102112012129. The reversal of 102112012127 is 721210211201.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 102112012127 - 210 = 102112011103 is a prime.

Together with 102112012129, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 102112012099 and 102112012108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (102112012129) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51056006063 + 51056006064.

It is an arithmetic number, because the mean of its divisors is an integer number (51056006064).

Almost surely, 2102112012127 is an apocalyptic number.

102112012127 is a deficient number, since it is larger than the sum of its proper divisors (1).

102112012127 is an equidigital number, since it uses as much as digits as its factorization.

102112012127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 112, while the sum is 20.

Adding to 102112012127 its reverse (721210211201), we get a palindrome (823322223328).

The spelling of 102112012127 in words is "one hundred two billion, one hundred twelve million, twelve thousand, one hundred twenty-seven".