| Base | Representation |
|---|---|
| bin | 11101101110000000010… |
| … | …10110100100001100000 |
| 3 | 10121121201101201020221121 |
| 4 | 32313000022310201200 |
| 5 | 113212234103424300 |
| 6 | 2101033511502024 |
| 7 | 133526404635220 |
| oct | 16670012644140 |
| 9 | 3547641636847 |
| 10 | 1021131311200 |
| 11 | 364072005850 |
| 12 | 145a9a987914 |
| 13 | 753a5167b90 |
| 14 | 375cca9c080 |
| 15 | 1b8669a081a |
| hex | edc02b4860 |
1021131311200 has 576 divisors, whose sum is σ = 3389603051520. Its totient is φ = 290055168000.
The previous prime is 1021131311197. The next prime is 1021131311209. The reversal of 1021131311200 is 21131311201.
It is a happy number.
It is a Harshad number since it is a multiple of its sum of digits (16).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1021131311209) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 63255130 + ... + 63271270.
It is an arithmetic number, because the mean of its divisors is an integer number (5884727520).
Almost surely, 21021131311200 is an apocalyptic number.
1021131311200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1021131311200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1694801525760).
1021131311200 is an abundant number, since it is smaller than the sum of its proper divisors (2368471740320).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1021131311200 is a wasteful number, since it uses less digits than its factorization.
1021131311200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16271 (or 16258 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 16.
Adding to 1021131311200 its reverse (21131311201), we get a palindrome (1042262622401).
Subtracting from 1021131311200 its reverse (21131311201), we obtain a palindrome (999999999999).
It can be divided in two parts, 1021131 and 311200, that added together give a palindrome (1332331).
The spelling of 1021131311200 in words is "one trillion, twenty-one billion, one hundred thirty-one million, three hundred eleven thousand, two hundred".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.093 sec. • engine limits •