Base | Representation |
---|---|
bin | 10111001110011010011011… |
… | …101100010101010001011111 |
3 | 111101200000110012211222002012 |
4 | 113032122123230111101133 |
5 | 101342023013211322143 |
6 | 1001125001151021435 |
7 | 30341525213034650 |
oct | 2716323354252137 |
9 | 441600405758065 |
10 | 102145524323423 |
11 | 2a601745609049 |
12 | b5585a150a87b |
13 | 44cc38791b219 |
14 | 1b31c26879527 |
15 | bc208d495418 |
hex | 5ce69bb1545f |
102145524323423 has 64 divisors (see below), whose sum is σ = 127596975722496. Its totient is φ = 79765171200000.
The previous prime is 102145524323419. The next prime is 102145524323471. The reversal of 102145524323423 is 324323425541201.
It is a cyclic number.
It is not a de Polignac number, because 102145524323423 - 22 = 102145524323419 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (102145524323413) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 973587338 + ... + 973692248.
It is an arithmetic number, because the mean of its divisors is an integer number (1993702745664).
Almost surely, 2102145524323423 is an apocalyptic number.
102145524323423 is a deficient number, since it is larger than the sum of its proper divisors (25451451399073).
102145524323423 is a wasteful number, since it uses less digits than its factorization.
102145524323423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 106104.
The product of its (nonzero) digits is 691200, while the sum is 41.
Adding to 102145524323423 its reverse (324323425541201), we get a palindrome (426468949864624).
The spelling of 102145524323423 in words is "one hundred two trillion, one hundred forty-five billion, five hundred twenty-four million, three hundred twenty-three thousand, four hundred twenty-three".
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