102541433 has 4 divisors (see below), whose sum is σ = 108573300. Its totient is φ = 96509568.

The previous prime is 102541409. The next prime is 102541441. The reversal of 102541433 is 334145201.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 334145201 = 13 ⋅25703477.

It can be written as a sum of positive squares in 2 ways, for example, as 91164304 + 11377129 = 9548^2 + 3373^2 .

It is a cyclic number.

It is not a de Polignac number, because 102541433 - 2¹⁰ = 102540409 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 102541399 and 102541408.

It is not an unprimeable number, because it can be changed into a prime (102541463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3015908 + ... + 3015941.

It is an arithmetic number, because the mean of its divisors is an integer number (27143325).

Almost surely, 2^102541433 is an apocalyptic number.

It is an amenable number.

102541433 is a deficient number, since it is larger than the sum of its proper divisors (6031867).

102541433 is an equidigital number, since it uses as much as digits as its factorization.

102541433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6031866.

The product of its (nonzero) digits is 1440, while the sum is 23.

The square root of 102541433 is about 10126.2743889350. The cubic root of 102541433 is about 468.0581310045.

Adding to 102541433 its reverse (334145201), we get a palindrome (436686634).

The spelling of 102541433 in words is "one hundred two million, five hundred forty-one thousand, four hundred thirty-three".