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103004113127 is a prime number
BaseRepresentation
bin101111111101110000…
…1100000100011100111
3100211212112102002201212
41133323201200203213
53141423023110002
6115152555342035
710304352341546
oct1377341404347
9324775362655
10103004113127
113a758155823
1217b67a5191b
139937004186
144db201815d
152a2cd42352
hex17fb8608e7

103004113127 has 2 divisors, whose sum is σ = 103004113128. Its totient is φ = 103004113126.

The previous prime is 103004113103. The next prime is 103004113129. The reversal of 103004113127 is 721311400301.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 103004113127 - 212 = 103004109031 is a prime.

Together with 103004113129, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (103004113129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51502056563 + 51502056564.

It is an arithmetic number, because the mean of its divisors is an integer number (51502056564).

Almost surely, 2103004113127 is an apocalyptic number.

103004113127 is a deficient number, since it is larger than the sum of its proper divisors (1).

103004113127 is an equidigital number, since it uses as much as digits as its factorization.

103004113127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 504, while the sum is 23.

Adding to 103004113127 its reverse (721311400301), we get a palindrome (824315513428).

The spelling of 103004113127 in words is "one hundred three billion, four million, one hundred thirteen thousand, one hundred twenty-seven".