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103031000111 = 137925461547
BaseRepresentation
bin101111111110100100…
…0000100110000101111
3100211221102000002202002
41133331020010300233
53142001414000421
6115155355522515
710305130023344
oct1377510046057
9324842002662
10103031000111
113a77134a376
1217b74a5943b
13993c759230
144db58167cb
152a303a3b0b
hex17fd204c2f

103031000111 has 4 divisors (see below), whose sum is σ = 110956461672. Its totient is φ = 95105538552.

The previous prime is 103031000087. The next prime is 103031000167. The reversal of 103031000111 is 111000130301.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 103031000111 - 210 = 103030999087 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 103031000092 and 103031000101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (103031080111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3962730761 + ... + 3962730786.

It is an arithmetic number, because the mean of its divisors is an integer number (27739115418).

Almost surely, 2103031000111 is an apocalyptic number.

103031000111 is a deficient number, since it is larger than the sum of its proper divisors (7925461561).

103031000111 is an equidigital number, since it uses as much as digits as its factorization.

103031000111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7925461560.

The product of its (nonzero) digits is 9, while the sum is 11.

Adding to 103031000111 its reverse (111000130301), we get a palindrome (214031130412).

The spelling of 103031000111 in words is "one hundred three billion, thirty-one million, one hundred eleven", and thus it is an aban number.

Divisors: 1 13 7925461547 103031000111