Base | Representation |
---|---|
bin | 10011001101000011… |
… | …00111101111001101 |
3 | 222121112010111021222 |
4 | 21212201213233031 |
5 | 132103331233031 |
6 | 4423015333125 |
7 | 513330521264 |
oct | 114641475715 |
9 | 28545114258 |
10 | 10310024141 |
11 | 441081580a |
12 | 1bb89811a5 |
13 | c83cb7b01 |
14 | 6db3c55db |
15 | 4051ebe7b |
hex | 266867bcd |
10310024141 has 2 divisors, whose sum is σ = 10310024142. Its totient is φ = 10310024140.
The previous prime is 10310024083. The next prime is 10310024143. The reversal of 10310024141 is 14142001301.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5880589225 + 4429434916 = 76685^2 + 66554^2 .
It is a cyclic number.
It is not a de Polignac number, because 10310024141 - 210 = 10310023117 is a prime.
Together with 10310024143, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10310024143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5155012070 + 5155012071.
It is an arithmetic number, because the mean of its divisors is an integer number (5155012071).
Almost surely, 210310024141 is an apocalyptic number.
It is an amenable number.
10310024141 is a deficient number, since it is larger than the sum of its proper divisors (1).
10310024141 is an equidigital number, since it uses as much as digits as its factorization.
10310024141 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 10310024141 its reverse (14142001301), we get a palindrome (24452025442).
The spelling of 10310024141 in words is "ten billion, three hundred ten million, twenty-four thousand, one hundred forty-one".
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