Base | Representation |
---|---|
bin | 1001011000010000110011… |
… | …0011111010010000000110 |
3 | 1100111212012002001110020200 |
4 | 2112010030303322100012 |
5 | 2322424324420142410 |
6 | 33533244322311330 |
7 | 2113022443465203 |
oct | 226041463722006 |
9 | 40455162043220 |
10 | 10312431412230 |
11 | 3316528762322 |
12 | 11a67504b8546 |
13 | 59a5c560ac4c |
14 | 2791a52accaa |
15 | 12d3b3b8d3c0 |
hex | 9610ccfa406 |
10312431412230 has 48 divisors (see below), whose sum is σ = 26951245663680. Its totient is φ = 2735733095424.
The previous prime is 10312431412193. The next prime is 10312431412237. The reversal of 10312431412230 is 3221413421301.
10312431412230 is a `hidden beast` number, since 1 + 0 + 3 + 1 + 2 + 431 + 4 + 1 + 223 + 0 = 666.
It is a super-3 number, since 3×103124314122303 (a number of 40 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10312431412194 and 10312431412203.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10312431412237) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 296828670 + ... + 296863409.
It is an arithmetic number, because the mean of its divisors is an integer number (561484284660).
Almost surely, 210312431412230 is an apocalyptic number.
10312431412230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
10312431412230 is an abundant number, since it is smaller than the sum of its proper divisors (16638814251450).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
10312431412230 is a wasteful number, since it uses less digits than its factorization.
10312431412230 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 593692285 (or 593692282 counting only the distinct ones).
The product of its (nonzero) digits is 3456, while the sum is 27.
Adding to 10312431412230 its reverse (3221413421301), we get a palindrome (13533844833531).
The spelling of 10312431412230 in words is "ten trillion, three hundred twelve billion, four hundred thirty-one million, four hundred twelve thousand, two hundred thirty".
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