Search a number
-
+
1031300030310 = 235118389423061
BaseRepresentation
bin11110000000111100100…
…01011001111101100110
310122120222001221201011220
433000132101121331212
5113344100301432220
62105434522441210
7134336401422504
oct17003621317546
93576861851156
101031300030310
1136840aa87a40
12147a58363206
1376335aa9634
1437cb53bd674
151bc5e589540
hexf01e459f66

1031300030310 has 128 divisors (see below), whose sum is σ = 2763373294080. Its totient is φ = 244224076800.

The previous prime is 1031300030291. The next prime is 1031300030317. The reversal of 1031300030310 is 130300031301.

It is a super-2 number, since 2×10313000303102 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 1031300030310.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1031300030317) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2226180 + ... + 2649240.

It is an arithmetic number, because the mean of its divisors is an integer number (21588853860).

Almost surely, 21031300030310 is an apocalyptic number.

1031300030310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 1031300030310, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1381686647040).

1031300030310 is an abundant number, since it is smaller than the sum of its proper divisors (1732073263770).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1031300030310 is a wasteful number, since it uses less digits than its factorization.

1031300030310 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 423254.

The product of its (nonzero) digits is 81, while the sum is 15.

Adding to 1031300030310 its reverse (130300031301), we get a palindrome (1161600061611).

Subtracting from 1031300030310 its reverse (130300031301), we obtain a palindrome (900999999009).

The spelling of 1031300030310 in words is "one trillion, thirty-one billion, three hundred million, thirty thousand, three hundred ten".

Divisors: 1 2 3 5 6 10 11 15 22 30 33 55 66 83 89 110 165 166 178 249 267 330 415 445 498 534 830 890 913 979 1245 1335 1826 1958 2490 2670 2739 2937 4565 4895 5478 5874 7387 9130 9790 13695 14685 14774 22161 27390 29370 36935 44322 73870 81257 110805 162514 221610 243771 406285 423061 487542 812570 846122 1218855 1269183 2115305 2437710 2538366 4230610 4653671 6345915 9307342 12691830 13961013 23268355 27922026 35114063 37652429 46536710 69805065 70228126 75304858 105342189 112957287 139610130 175570315 188262145 210684378 225914574 351140630 376524290 386254693 414176719 526710945 564786435 772509386 828353438 1053421890 1129572870 1158764079 1242530157 1931273465 2070883595 2317528158 2485060314 3125151607 3862546930 4141767190 5793820395 6212650785 6250303214 9375454821 11587640790 12425301570 15625758035 18750909642 31251516070 34376667677 46877274105 68753335354 93754548210 103130003031 171883338385 206260006062 343766676770 515650015155 1031300030310