Base | Representation |
---|---|
bin | 1001011000111111101000… |
… | …1101110101000001101011 |
3 | 1100120001122022020102121100 |
4 | 2112033322031311001223 |
5 | 2323131102102410410 |
6 | 33543124100012443 |
7 | 2113646142562224 |
oct | 226177215650153 |
9 | 40501568212540 |
10 | 10325004341355 |
11 | 332089a862040 |
12 | 11a907b091123 |
13 | 59b84a380692 |
14 | 279a3902824b |
15 | 12d89c8808c0 |
hex | 963fa37506b |
10325004341355 has 96 divisors (see below), whose sum is σ = 19966242059712. Its totient is φ = 4893790003200.
The previous prime is 10325004341341. The next prime is 10325004341357. The reversal of 10325004341355 is 55314340052301.
10325004341355 is a `hidden beast` number, since 10 + 3 + 2 + 500 + 4 + 3 + 4 + 135 + 5 = 666.
It is not a de Polignac number, because 10325004341355 - 234 = 10307824472171 is a prime.
It is not an unprimeable number, because it can be changed into a prime (10325004341357) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 2818945 + ... + 5347565.
It is an arithmetic number, because the mean of its divisors is an integer number (207981688122).
Almost surely, 210325004341355 is an apocalyptic number.
10325004341355 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
10325004341355 is a deficient number, since it is larger than the sum of its proper divisors (9641237718357).
10325004341355 is a wasteful number, since it uses less digits than its factorization.
10325004341355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2528829 (or 2528826 counting only the distinct ones).
The product of its (nonzero) digits is 108000, while the sum is 36.
Adding to 10325004341355 its reverse (55314340052301), we get a palindrome (65639344393656).
The spelling of 10325004341355 in words is "ten trillion, three hundred twenty-five billion, four million, three hundred forty-one thousand, three hundred fifty-five".
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