104023000111 has 4 divisors (see below), whose sum is σ = 105095402272. Its totient is φ = 102950597952.

The previous prime is 104023000069. The next prime is 104023000127. The reversal of 104023000111 is 111000320401.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 111000320401 = 23 ⋅4826100887.

It is a cyclic number.

It is not a de Polignac number, because 104023000111 - 2¹¹ = 104022998063 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 104023000091 and 104023000100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (104023000811) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 536200935 + ... + 536201128.

It is an arithmetic number, because the mean of its divisors is an integer number (26273850568).

Almost surely, 2^104023000111 is an apocalyptic number.

104023000111 is a deficient number, since it is larger than the sum of its proper divisors (1072402161).

104023000111 is an equidigital number, since it uses as much as digits as its factorization.

104023000111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1072402160.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 104023000111 its reverse (111000320401), we get a palindrome (215023320512).

The spelling of 104023000111 in words is "one hundred four billion, twenty-three million, one hundred eleven", and thus it is an aban number.