10411312013 has 2 divisors, whose sum is σ = 10411312014. Its totient is φ = 10411312012.

The previous prime is 10411312001. The next prime is 10411312061. The reversal of 10411312013 is 31021311401.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7949862244 + 2461449769 = 89162^2 + 49613^2 .

It is a cyclic number.

It is not a de Polignac number, because 10411312013 - 2⁶ = 10411311949 is a prime.

It is a super-2 number, since 2×10411312013² (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 10411311982 and 10411312000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10411312073) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5205656006 + 5205656007.

It is an arithmetic number, because the mean of its divisors is an integer number (5205656007).

Almost surely, 2^10411312013 is an apocalyptic number.

It is an amenable number.

10411312013 is a deficient number, since it is larger than the sum of its proper divisors (1).

10411312013 is an equidigital number, since it uses as much as digits as its factorization.

10411312013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 10411312013 its reverse (31021311401), we get a palindrome (41432623414).

The spelling of 10411312013 in words is "ten billion, four hundred eleven million, three hundred twelve thousand, thirteen".