Base | Representation |
---|---|
bin | 11110101011110110000… |
… | …10000000101010011111 |
3 | 10201210102010222212221222 |
4 | 33111323002000222133 |
5 | 114233232231041340 |
6 | 2124204130443555 |
7 | 136113210404522 |
oct | 17257302005237 |
9 | 3653363885858 |
10 | 1054331112095 |
11 | 377159476628 |
12 | 1504054335bb |
13 | 7856642bc91 |
14 | 3905c07cbb9 |
15 | 1c65b4888b5 |
hex | f57b080a9f |
1054331112095 has 4 divisors (see below), whose sum is σ = 1265197334520. Its totient is φ = 843464889672.
The previous prime is 1054331112049. The next prime is 1054331112137. The reversal of 1054331112095 is 5902111334501.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1054331112095 - 220 = 1054330063519 is a prime.
It is a super-2 number, since 2×10543311120952 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 105433111205 + ... + 105433111214.
It is an arithmetic number, because the mean of its divisors is an integer number (316299333630).
Almost surely, 21054331112095 is an apocalyptic number.
1054331112095 is a deficient number, since it is larger than the sum of its proper divisors (210866222425).
1054331112095 is an equidigital number, since it uses as much as digits as its factorization.
1054331112095 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 210866222424.
The product of its (nonzero) digits is 16200, while the sum is 35.
Adding to 1054331112095 its reverse (5902111334501), we get a palindrome (6956442446596).
The spelling of 1054331112095 in words is "one trillion, fifty-four billion, three hundred thirty-one million, one hundred twelve thousand, ninety-five".
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