Base | Representation |
---|---|
bin | 11001000000101101011111… |
… | …100001010111101011111111 |
3 | 112102110220020211100220010002 |
4 | 121000231133201113223333 |
5 | 103404220010030014101 |
6 | 1025541150150104515 |
7 | 32112144535522454 |
oct | 3100553741275377 |
9 | 472426224326102 |
10 | 110000010001151 |
11 | 3205a818a51206 |
12 | 104068a494b13b |
13 | 494bc583936ba |
14 | 1d240593c582b |
15 | cab54553ad6b |
hex | 640b5f857aff |
110000010001151 has 2 divisors, whose sum is σ = 110000010001152. Its totient is φ = 110000010001150.
The previous prime is 110000010001093. The next prime is 110000010001163. The reversal of 110000010001151 is 151100010000011.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (151100010000011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 110000010001151 - 26 = 110000010001087 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110000010001051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000005000575 + 55000005000576.
It is an arithmetic number, because the mean of its divisors is an integer number (55000005000576).
Almost surely, 2110000010001151 is an apocalyptic number.
110000010001151 is a deficient number, since it is larger than the sum of its proper divisors (1).
110000010001151 is an equidigital number, since it uses as much as digits as its factorization.
110000010001151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5, while the sum is 11.
Adding to 110000010001151 its reverse (151100010000011), we get a palindrome (261100020001162).
The spelling of 110000010001151 in words is "one hundred ten trillion, ten million, one thousand, one hundred fifty-one".
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