Base | Representation |
---|---|
bin | 10000000000011110010… |
… | …100110100010100000100 |
3 | 10220011100022110021012121 |
4 | 100000132110310110010 |
5 | 121010320210321122 |
6 | 2201201542455324 |
7 | 142321350064612 |
oct | 20003624642404 |
9 | 3804308407177 |
10 | 1100020401412 |
11 | 394574925969 |
12 | 159236734544 |
13 | 7c96809c30a |
14 | 3b3540986b2 |
15 | 1d932680bc7 |
hex | 1001e534504 |
1100020401412 has 12 divisors (see below), whose sum is σ = 2038273096860. Its totient is φ = 517656659456.
The previous prime is 1100020401353. The next prime is 1100020401437. The reversal of 1100020401412 is 2141040200011.
It is a happy number.
It can be written as a sum of positive squares in 2 ways, for example, as 563001111556 + 537019289856 = 750334^2 + 732816^2 .
It is a super-2 number, since 2×11000204014122 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8088385237 + ... + 8088385372.
It is an arithmetic number, because the mean of its divisors is an integer number (169856091405).
Almost surely, 21100020401412 is an apocalyptic number.
It is an amenable number.
1100020401412 is a deficient number, since it is larger than the sum of its proper divisors (938252695448).
1100020401412 is a wasteful number, since it uses less digits than its factorization.
1100020401412 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16176770630 (or 16176770628 counting only the distinct ones).
The product of its (nonzero) digits is 64, while the sum is 16.
Adding to 1100020401412 its reverse (2141040200011), we get a palindrome (3241060601423).
The spelling of 1100020401412 in words is "one trillion, one hundred billion, twenty million, four hundred one thousand, four hundred twelve".
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