1100020401413 has 8 divisors (see below), whose sum is σ = 1105280784888. Its totient is φ = 1094770263744.

The previous prime is 1100020401353. The next prime is 1100020401437. The reversal of 1100020401413 is 3141040200011.

It is a happy number.

It can be written as a sum of positive squares in 4 ways, for example, as 864987422209 + 235032979204 = 930047^2 + 484802^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1100020401413 - 2¹⁰ = 1100020400389 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1100020401391 and 1100020401400.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1100020461413) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2346170 + ... + 2775707.

It is an arithmetic number, because the mean of its divisors is an integer number (138160098111).

Almost surely, 2^{1100020401413} is an apocalyptic number.

It is an amenable number.

1100020401413 is a deficient number, since it is larger than the sum of its proper divisors (5260383475).

1100020401413 is an equidigital number, since it uses as much as digits as its factorization.

1100020401413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5122903.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 1100020401413 its reverse (3141040200011), we get a palindrome (4241060601424).

The spelling of 1100020401413 in words is "one trillion, one hundred billion, twenty million, four hundred one thousand, four hundred thirteen".