110003330112 has 112 divisors (see below), whose sum is σ = 321910569792. Its totient is φ = 32932362240.

The previous prime is 110003330083. The next prime is 110003330117. The reversal of 110003330112 is 211033300011.

It is a junction number, because it is equal to n+sod(n) for n = 110003330091 and 110003330100.

It is not an unprimeable number, because it can be changed into a prime (110003330117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 503214 + ... + 687917.

It is an arithmetic number, because the mean of its divisors is an integer number (2874201516).

Almost surely, 2^110003330112 is an apocalyptic number.

110003330112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

110003330112 is an abundant number, since it is smaller than the sum of its proper divisors (211907239680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

110003330112 is a wasteful number, since it uses less digits than its factorization.

110003330112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1191196 (or 1191186 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 110003330112 its reverse (211033300011), we get a palindrome (321036630123).

The spelling of 110003330112 in words is "one hundred ten billion, three million, three hundred thirty thousand, one hundred twelve".