110010000000181 has 2 divisors, whose sum is σ = 110010000000182. Its totient is φ = 110010000000180.

The previous prime is 110010000000169. The next prime is 110010000000203. The reversal of 110010000000181 is 181000000010011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 101712086028081 + 8297913972100 = 10085241^2 + 2880610^2 .

It is a cyclic number.

It is not a de Polignac number, because 110010000000181 - 2¹¹ = 110009999998133 is a prime.

It is a super-2 number, since 2×110010000000181² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110010000000881) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005000000090 + 55005000000091.

It is an arithmetic number, because the mean of its divisors is an integer number (55005000000091).

Almost surely, 2^{110010000000181} is an apocalyptic number.

It is an amenable number.

110010000000181 is a deficient number, since it is larger than the sum of its proper divisors (1).

110010000000181 is an equidigital number, since it uses as much as digits as its factorization.

110010000000181 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8, while the sum is 13.

Adding to 110010000000181 its reverse (181000000010011), we get a palindrome (291010000010192).

The spelling of 110010000000181 in words is "one hundred ten trillion, ten billion, one hundred eighty-one", and thus it is an aban number.