Base | Representation |
---|---|
bin | 11001000000110110110011… |
… | …100100110000110010101111 |
3 | 112102111212001202100010010112 |
4 | 121000312303210300302233 |
5 | 103404401000042024101 |
6 | 1025545522335130235 |
7 | 32112650414203223 |
oct | 3100666344606257 |
9 | 472455052303115 |
10 | 110010010111151 |
11 | 32063a8a830927 |
12 | 1040881597397b |
13 | 494cb900bbc57 |
14 | 1d24727576783 |
15 | cab92d41b6bb |
hex | 640db3930caf |
110010010111151 has 2 divisors, whose sum is σ = 110010010111152. Its totient is φ = 110010010111150.
The previous prime is 110010010111147. The next prime is 110010010111187. The reversal of 110010010111151 is 151111010010011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 110010010111151 - 22 = 110010010111147 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110010010101151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005005055575 + 55005005055576.
It is an arithmetic number, because the mean of its divisors is an integer number (55005005055576).
Almost surely, 2110010010111151 is an apocalyptic number.
110010010111151 is a deficient number, since it is larger than the sum of its proper divisors (1).
110010010111151 is an equidigital number, since it uses as much as digits as its factorization.
110010010111151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5, while the sum is 14.
Adding to 110010010111151 its reverse (151111010010011), we get a palindrome (261121020121162).
The spelling of 110010010111151 in words is "one hundred ten trillion, ten billion, ten million, one hundred eleven thousand, one hundred fifty-one".
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