1100101012013 has 4 divisors (see below), whose sum is σ = 1100871932160. Its totient is φ = 1099330091868.

The previous prime is 1100101012007. The next prime is 1100101012027. The reversal of 1100101012013 is 3102101010011.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1100101012013 - 2¹⁰ = 1100101010989 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1100101011985 and 1100101012003.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1100101012613) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 385457933 + ... + 385460786.

It is an arithmetic number, because the mean of its divisors is an integer number (275217983040).

Almost surely, 2^{1100101012013} is an apocalyptic number.

It is an amenable number.

1100101012013 is a deficient number, since it is larger than the sum of its proper divisors (770920147).

1100101012013 is an equidigital number, since it uses as much as digits as its factorization.

1100101012013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 770920146.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 1100101012013 its reverse (3102101010011), we get a palindrome (4202202022024).

The spelling of 1100101012013 in words is "one trillion, one hundred billion, one hundred one million, twelve thousand, thirteen".