Base | Representation |
---|---|
bin | 10100011111011101… |
… | …01011011111011111 |
3 | 1001101200220121200012 |
4 | 22033232223133133 |
5 | 140012314010442 |
6 | 5015352153435 |
7 | 536423422361 |
oct | 121756533737 |
9 | 31350817605 |
10 | 11001313247 |
11 | 4735a55521 |
12 | 217039887b |
13 | 1064297312 |
14 | 765132d31 |
15 | 445c4d582 |
hex | 28fbab7df |
11001313247 has 2 divisors, whose sum is σ = 11001313248. Its totient is φ = 11001313246.
The previous prime is 11001313187. The next prime is 11001313249. The reversal of 11001313247 is 74231310011.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (74231310011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11001313247 - 216 = 11001247711 is a prime.
Together with 11001313249, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11001313249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500656623 + 5500656624.
It is an arithmetic number, because the mean of its divisors is an integer number (5500656624).
Almost surely, 211001313247 is an apocalyptic number.
11001313247 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001313247 is an equidigital number, since it uses as much as digits as its factorization.
11001313247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 23.
Adding to 11001313247 its reverse (74231310011), we get a palindrome (85232623258).
The spelling of 11001313247 in words is "eleven billion, one million, three hundred thirteen thousand, two hundred forty-seven".
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