110013311213100 has 54 divisors (see below), whose sum is σ = 344830612149660. Its totient is φ = 29336882989920.

The previous prime is 110013311213063. The next prime is 110013311213101. The reversal of 110013311213100 is 1312113310011.

110013311213100 is a `hidden beast` number, since 1 + 1 + 0 + 0 + 1 + 331 + 1 + 21 + 310 + 0 = 666.

It is a super-2 number, since 2×110013311213100² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is not an unprimeable number, because it can be changed into a prime (110013311213101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 61118505330 + ... + 61118507129.

Almost surely, 2^{110013311213100} is an apocalyptic number.

110013311213100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

110013311213100 is an abundant number, since it is smaller than the sum of its proper divisors (234817300936560).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

110013311213100 is a wasteful number, since it uses less digits than its factorization.

110013311213100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 122237012479 (or 122237012469 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 18.

Adding to 110013311213100 its reverse (1312113310011), we get a palindrome (111325424523111).

It can be divided in two parts, 110013 and 311213100, that added together give a palindrome (311323113).

The spelling of 110013311213100 in words is "one hundred ten trillion, thirteen billion, three hundred eleven million, two hundred thirteen thousand, one hundred".