110021220013433 has 12 divisors (see below), whose sum is σ = 115226167921020. Its totient is φ = 105033818647296.

The previous prime is 110021220013387. The next prime is 110021220013451. The reversal of 110021220013433 is 334310022120011.

It can be written as a sum of positive squares in 6 ways, for example, as 19437975957904 + 90583244055529 = 4408852^2 + 9517523^2 .

It is not a de Polignac number, because 110021220013433 - 2¹⁰ = 110021220012409 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 110021220013399 and 110021220013408.

It is not an unprimeable number, because it can be changed into a prime (110021220013933) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 734879660 + ... + 735029357.

It is an arithmetic number, because the mean of its divisors is an integer number (9602180660085).

Almost surely, 2^{110021220013433} is an apocalyptic number.

It is an amenable number.

110021220013433 is a deficient number, since it is larger than the sum of its proper divisors (5204947907587).

110021220013433 is an equidigital number, since it uses as much as digits as its factorization.

110021220013433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1469909164 (or 1469909135 counting only the distinct ones).

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 110021220013433 its reverse (334310022120011), we get a palindrome (444331242133444).

The spelling of 110021220013433 in words is "one hundred ten trillion, twenty-one billion, two hundred twenty million, thirteen thousand, four hundred thirty-three".