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11003211341 is a prime number
BaseRepresentation
bin10100011111101011…
…11010111001001101
31001101211111001100222
422033311322321031
5140013310230331
65015501001125
7536445516233
oct121765727115
931354431328
1011003211341
1147370315a1
122170b531a5
1310647b0255
147654a8953
15445ec5b7b
hex28fd7ae4d

11003211341 has 2 divisors, whose sum is σ = 11003211342. Its totient is φ = 11003211340.

The previous prime is 11003211283. The next prime is 11003211343. The reversal of 11003211341 is 14311230011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9057519241 + 1945692100 = 95171^2 + 44110^2 .

It is a cyclic number.

It is not a de Polignac number, because 11003211341 - 218 = 11002949197 is a prime.

It is a super-2 number, since 2×110032113412 (a number of 21 digits) contains 22 as substring.

Together with 11003211343, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11003211343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5501605670 + 5501605671.

It is an arithmetic number, because the mean of its divisors is an integer number (5501605671).

Almost surely, 211003211341 is an apocalyptic number.

It is an amenable number.

11003211341 is a deficient number, since it is larger than the sum of its proper divisors (1).

11003211341 is an equidigital number, since it uses as much as digits as its factorization.

11003211341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 11003211341 its reverse (14311230011), we get a palindrome (25314441352).

The spelling of 11003211341 in words is "eleven billion, three million, two hundred eleven thousand, three hundred forty-one".