Base | Representation |
---|---|
bin | 10000000000110000110… |
… | …110001000000100111000 |
3 | 10220012010222010120002120 |
4 | 100000300312020010320 |
5 | 121011434231414000 |
6 | 2201252442401240 |
7 | 142332142140504 |
oct | 20006066100470 |
9 | 3805128116076 |
10 | 1100331123000 |
11 | 39471426266a |
12 | 159302800220 |
13 | 7c9b7582245 |
14 | 3b38345d304 |
15 | 1d94eaab6a0 |
hex | 10030d88138 |
1100331123000 has 128 divisors (see below), whose sum is σ = 3525818137920. Its totient is φ = 285491289600.
The previous prime is 1100331122959. The next prime is 1100331123019. The reversal of 1100331123000 is 3211330011.
It is a super-2 number, since 2×11003311230002 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4845447 + ... + 5067446.
Almost surely, 21100331123000 is an apocalyptic number.
1100331123000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1100331123000 is an abundant number, since it is smaller than the sum of its proper divisors (2425487014920).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1100331123000 is a wasteful number, since it uses less digits than its factorization.
1100331123000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9912954 (or 9912940 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 1100331123000 its reverse (3211330011), we get a palindrome (1103542453011).
The spelling of 1100331123000 in words is "one trillion, one hundred billion, three hundred thirty-one million, one hundred twenty-three thousand".
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