110043312100 has 72 divisors (see below), whose sum is σ = 241180063488. Its totient is φ = 43579670400.

The previous prime is 110043312089. The next prime is 110043312133. The reversal of 110043312100 is 1213340011.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4095309 + ... + 4122091.

It is an arithmetic number, because the mean of its divisors is an integer number (3349723104).

Almost surely, 2^110043312100 is an apocalyptic number.

110043312100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 110043312100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (120590031744).

110043312100 is an abundant number, since it is smaller than the sum of its proper divisors (131136751388).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

110043312100 is a wasteful number, since it uses less digits than its factorization.

110043312100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27205 (or 27198 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 110043312100 its reverse (1213340011), we get a palindrome (111256652111).

The spelling of 110043312100 in words is "one hundred ten billion, forty-three million, three hundred twelve thousand, one hundred".