11005342803 has 32 divisors (see below), whose sum is σ = 20066726400. Its totient is φ = 5805014688.

The previous prime is 11005342769. The next prime is 11005342807. The reversal of 11005342803 is 30824350011.

It is a happy number.

11005342803 is a `hidden beast` number, since 1 + 100 + 534 + 28 + 0 + 3 = 666.

It is not a de Polignac number, because 11005342803 - 2⁶ = 11005342739 is a prime.

It is a super-3 number, since 3×11005342803³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is not an unprimeable number, because it can be changed into a prime (11005342807) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2237133 + ... + 2242046.

It is an arithmetic number, because the mean of its divisors is an integer number (627085200).

Almost surely, 2^11005342803 is an apocalyptic number.

11005342803 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

11005342803 is a deficient number, since it is larger than the sum of its proper divisors (9061383597).

11005342803 is a wasteful number, since it uses less digits than its factorization.

11005342803 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4479208 (or 4479202 counting only the distinct ones).

The product of its (nonzero) digits is 2880, while the sum is 27.

Adding to 11005342803 its reverse (30824350011), we get a palindrome (41829692814).

The spelling of 11005342803 in words is "eleven billion, five million, three hundred forty-two thousand, eight hundred three".