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110212202212020 = 223353124763265871
BaseRepresentation
bin11001000011110011000111…
…001010011010101010110100
3112110020011221212110001201000
4121003303013022122222310
5103421204042231241040
61030222441533403300
732133366053536656
oct3103630712325264
9473204855401630
10110212202212020
1132131806a16937
121043ba43639530
134965c7360521c
141d3042883a6d6
15cb1d1404c130
hex643cc729aab4

110212202212020 has 192 divisors, whose sum is σ = 353958754222080. Its totient is φ = 28440603100800.

The previous prime is 110212202211983. The next prime is 110212202212031. The reversal of 110212202212020 is 20212202212011.

It is a happy number.

110212202212020 is a `hidden beast` number, since 1 + 1 + 0 + 21 + 220 + 221 + 202 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 110212202211984 and 110212202212002.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 414399685 + ... + 414665555.

It is an arithmetic number, because the mean of its divisors is an integer number (1843535178240).

Almost surely, 2110212202212020 is an apocalyptic number.

110212202212020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 110212202212020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (176979377111040).

110212202212020 is an abundant number, since it is smaller than the sum of its proper divisors (243746552010060).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

110212202212020 is a wasteful number, since it uses less digits than its factorization.

110212202212020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 290683 (or 290675 counting only the distinct ones).

The product of its (nonzero) digits is 128, while the sum is 18.

Adding to 110212202212020 its reverse (20212202212011), we get a palindrome (130424404424031).

Subtracting from 110212202212020 its reverse (20212202212011), we obtain a palindrome (90000000000009).

The spelling of 110212202212020 in words is "one hundred ten trillion, two hundred twelve billion, two hundred two million, two hundred twelve thousand, twenty".