11025214031 has 4 divisors (see below), whose sum is σ = 11873307432. Its totient is φ = 10177120632.

The previous prime is 11025214003. The next prime is 11025214049. The reversal of 11025214031 is 13041252011.

11025214031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13041252011 = 23 ⋅567010957.

It is a cyclic number.

It is not a de Polignac number, because 11025214031 - 2²⁶ = 10958105167 is a prime.

It is a super-2 number, since 2×11025214031² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11025213994 and 11025214012.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11025214831) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 424046681 + ... + 424046706.

It is an arithmetic number, because the mean of its divisors is an integer number (2968326858).

Almost surely, 2^11025214031 is an apocalyptic number.

11025214031 is a deficient number, since it is larger than the sum of its proper divisors (848093401).

11025214031 is an equidigital number, since it uses as much as digits as its factorization.

11025214031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 848093400.

The product of its (nonzero) digits is 240, while the sum is 20.

Adding to 11025214031 its reverse (13041252011), we get a palindrome (24066466042).

The spelling of 11025214031 in words is "eleven billion, twenty-five million, two hundred fourteen thousand, thirty-one".