11033000441130 has 32 divisors (see below), whose sum is σ = 26741371373568. Its totient is φ = 2913003416000.

The previous prime is 11033000441081. The next prime is 11033000441159. The reversal of 11033000441130 is 3114400033011.

It is a junction number, because it is equal to n+sod(n) for n = 11033000441097 and 11033000441106.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1820624106 + ... + 1820630165.

It is an arithmetic number, because the mean of its divisors is an integer number (835667855424).

Almost surely, 2^{11033000441130} is an apocalyptic number.

11033000441130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11033000441130 is an abundant number, since it is smaller than the sum of its proper divisors (15708370932438).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11033000441130 is a wasteful number, since it uses less digits than its factorization.

11033000441130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3641254382.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 11033000441130 its reverse (3114400033011), we get a palindrome (14147400474141).

The spelling of 11033000441130 in words is "eleven trillion, thirty-three billion, four hundred forty-one thousand, one hundred thirty".