Search a number
-
+
11034331300 = 2252254343391
BaseRepresentation
bin10100100011011001…
…01000100010100100
31001111000001002221001
422101230220202210
5140044242100200
65022532003044
7540304161046
oct122154504244
931430032831
1011034331300
114752657473
12217b460484
13106b087c25
14769689a96
15448ac176a
hex291b288a4

11034331300 has 36 divisors (see below), whose sum is σ = 23954466816. Its totient is φ = 4411895200.

The previous prime is 11034331291. The next prime is 11034331361. The reversal of 11034331300 is 313343011.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 232605 + ... + 275995.

It is an arithmetic number, because the mean of its divisors is an integer number (665401856).

Almost surely, 211034331300 is an apocalyptic number.

11034331300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

11034331300 is an abundant number, since it is smaller than the sum of its proper divisors (12920135516).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11034331300 is a wasteful number, since it uses less digits than its factorization.

11034331300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 45948 (or 45941 counting only the distinct ones).

The product of its (nonzero) digits is 324, while the sum is 19.

Adding to 11034331300 its reverse (313343011), we get a palindrome (11347674311).

The spelling of 11034331300 in words is "eleven billion, thirty-four million, three hundred thirty-one thousand, three hundred".

Divisors: 1 2 4 5 10 20 25 50 100 2543 5086 10172 12715 25430 43391 50860 63575 86782 127150 173564 216955 254300 433910 867820 1084775 2169550 4339100 110343313 220686626 441373252 551716565 1103433130 2206866260 2758582825 5517165650 11034331300