11034343301 has 2 divisors, whose sum is σ = 11034343302. Its totient is φ = 11034343300.

The previous prime is 11034343283. The next prime is 11034343303. The reversal of 11034343301 is 10334343011.

11034343301 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8747112676 + 2287230625 = 93526^2 + 47825^2 .

It is a cyclic number.

It is not a de Polignac number, because 11034343301 - 2¹⁴ = 11034326917 is a prime.

Together with 11034343303, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11034343303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5517171650 + 5517171651.

It is an arithmetic number, because the mean of its divisors is an integer number (5517171651).

Almost surely, 2^11034343301 is an apocalyptic number.

It is an amenable number.

11034343301 is a deficient number, since it is larger than the sum of its proper divisors (1).

11034343301 is an equidigital number, since it uses as much as digits as its factorization.

11034343301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 11034343301 its reverse (10334343011), we get a palindrome (21368686312).

The spelling of 11034343301 in words is "eleven billion, thirty-four million, three hundred forty-three thousand, three hundred one".