Base | Representation |
---|---|
bin | 10100100100000100… |
… | …10110011001000011 |
3 | 1001111101202100000122 |
4 | 22102002112121003 |
5 | 140102221233011 |
6 | 5023254010455 |
7 | 540403441163 |
oct | 122202263103 |
9 | 31441670018 |
10 | 11040024131 |
11 | 4755895594 |
12 | 2181346a2b |
13 | 106c2cc176 |
14 | 76a32c5a3 |
15 | 4493483db |
hex | 292096643 |
11040024131 has 2 divisors, whose sum is σ = 11040024132. Its totient is φ = 11040024130.
The previous prime is 11040024109. The next prime is 11040024133. The reversal of 11040024131 is 13142004011.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11040024131 - 226 = 10972915267 is a prime.
It is a super-2 number, since 2×110400241312 (a number of 21 digits) contains 22 as substring.
Together with 11040024133, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (11040024133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5520012065 + 5520012066.
It is an arithmetic number, because the mean of its divisors is an integer number (5520012066).
Almost surely, 211040024131 is an apocalyptic number.
11040024131 is a deficient number, since it is larger than the sum of its proper divisors (1).
11040024131 is an equidigital number, since it uses as much as digits as its factorization.
11040024131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 11040024131 its reverse (13142004011), we get a palindrome (24182028142).
The spelling of 11040024131 in words is "eleven billion, forty million, twenty-four thousand, one hundred thirty-one".
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