1104131324111 has 2 divisors, whose sum is σ = 1104131324112. Its totient is φ = 1104131324110.

The previous prime is 1104131324099. The next prime is 1104131324113. The reversal of 1104131324111 is 1114231314011.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1104131324111 is a prime.

It is a super-2 number, since 2×1104131324111² (a number of 25 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 1104131324113, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1104131324113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 552065662055 + 552065662056.

It is an arithmetic number, because the mean of its divisors is an integer number (552065662056).

Almost surely, 2^{1104131324111} is an apocalyptic number.

1104131324111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1104131324111 is an equidigital number, since it uses as much as digits as its factorization.

1104131324111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 23.

Adding to 1104131324111 its reverse (1114231314011), we get a palindrome (2218362638122).

The spelling of 1104131324111 in words is "one trillion, one hundred four billion, one hundred thirty-one million, three hundred twenty-four thousand, one hundred eleven".