11044155264413 has 2 divisors, whose sum is σ = 11044155264414. Its totient is φ = 11044155264412.

The previous prime is 11044155264407. The next prime is 11044155264419. The reversal of 11044155264413 is 31446255144011.

It is a happy number.

It is a balanced prime because it is at equal distance from previous prime (11044155264407) and next prime (11044155264419).

It can be written as a sum of positive squares in only one way, i.e., 10584175608889 + 459979655524 = 3253333^2 + 678218^2 .

It is an emirp because it is prime and its reverse (31446255144011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11044155264413 - 2¹⁴ = 11044155248029 is a prime.

It is a super-2 number, since 2×11044155264413² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11044155264419) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5522077632206 + 5522077632207.

It is an arithmetic number, because the mean of its divisors is an integer number (5522077632207).

Almost surely, 2^{11044155264413} is an apocalyptic number.

It is an amenable number.

11044155264413 is a deficient number, since it is larger than the sum of its proper divisors (1).

11044155264413 is an equidigital number, since it uses as much as digits as its factorization.

11044155264413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 230400, while the sum is 41.

The spelling of 11044155264413 in words is "eleven trillion, forty-four billion, one hundred fifty-five million, two hundred sixty-four thousand, four hundred thirteen".