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31446255144011 is a prime number
BaseRepresentation
bin1110010011001101001101…
…10111100000110001001011
311010100020021120220022220212
413021212212313200301023
513110203412304102021
6150514113222111335
76423626342313431
oct711464667406113
9133306246808825
1031446255144011
11a024311254694
12363a5b327b54b
1314714a4cb8306
147aa014bcad51
15397ec8b5685b
hex1c99a6de0c4b

31446255144011 has 2 divisors, whose sum is σ = 31446255144012. Its totient is φ = 31446255144010.

The previous prime is 31446255143993. The next prime is 31446255144013. The reversal of 31446255144011 is 11044155264413.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (11044155264413) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-31446255144011 is a prime.

Together with 31446255144013, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 31446255144011.

It is not a weakly prime, because it can be changed into another prime (31446255144013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15723127572005 + 15723127572006.

It is an arithmetic number, because the mean of its divisors is an integer number (15723127572006).

Almost surely, 231446255144011 is an apocalyptic number.

31446255144011 is a deficient number, since it is larger than the sum of its proper divisors (1).

31446255144011 is an equidigital number, since it uses as much as digits as its factorization.

31446255144011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 230400, while the sum is 41.

The spelling of 31446255144011 in words is "thirty-one trillion, four hundred forty-six billion, two hundred fifty-five million, one hundred forty-four thousand, eleven".