1110013423 has 2 divisors, whose sum is σ = 1110013424. Its totient is φ = 1110013422.

The previous prime is 1110013409. The next prime is 1110013439. The reversal of 1110013423 is 3243100111.

It is an a-pointer prime, because the next prime (1110013439) can be obtained adding 1110013423 to its sum of digits (16).

It is a weak prime.

It is an emirp because it is prime and its reverse (3243100111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1110013423 - 2⁵ = 1110013391 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1110013397 and 1110013406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1110013493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 555006711 + 555006712.

It is an arithmetic number, because the mean of its divisors is an integer number (555006712).

Almost surely, 2^1110013423 is an apocalyptic number.

1110013423 is a deficient number, since it is larger than the sum of its proper divisors (1).

1110013423 is an equidigital number, since it uses as much as digits as its factorization.

1110013423 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 1110013423 is about 33316.8639430544. The cubic root of 1110013423 is about 1035.4029790527.

Adding to 1110013423 its reverse (3243100111), we get a palindrome (4353113534).

The spelling of 1110013423 in words is "one billion, one hundred ten million, thirteen thousand, four hundred twenty-three".