Base | Representation |
---|---|
bin | 11001010000110111010111… |
… | …010110100111100110001100 |
3 | 112120102000122102221222121212 |
4 | 121100313113112213212030 |
5 | 104030412012213323040 |
6 | 1032151141351113552 |
7 | 32255304255104366 |
oct | 3120672726474614 |
9 | 476360572858555 |
10 | 111110122011020 |
11 | 324485a1270950 |
12 | 10565a770728b8 |
13 | 49cc841116262 |
14 | 1d61a8984bd36 |
15 | cca368b22d65 |
hex | 650dd75a798c |
111110122011020 has 96 divisors (see below), whose sum is σ = 269651975201280. Its totient is φ = 38007853194240.
The previous prime is 111110122010947. The next prime is 111110122011023. The reversal of 111110122011020 is 20110221011111.
It is a junction number, because it is equal to n+sod(n) for n = 111110122010986 and 111110122011004.
It is not an unprimeable number, because it can be changed into a prime (111110122011023) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 44360 + ... + 14907119.
It is an arithmetic number, because the mean of its divisors is an integer number (2808874741680).
Almost surely, 2111110122011020 is an apocalyptic number.
111110122011020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 111110122011020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (134825987600640).
111110122011020 is an abundant number, since it is smaller than the sum of its proper divisors (158541853190260).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
111110122011020 is a wasteful number, since it uses less digits than its factorization.
111110122011020 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14953503 (or 14953501 counting only the distinct ones).
The product of its (nonzero) digits is 8, while the sum is 14.
Adding to 111110122011020 its reverse (20110221011111), we get a palindrome (131220343022131).
Subtracting from 111110122011020 its reverse (20110221011111), we obtain a palindrome (90999900999909).
The spelling of 111110122011020 in words is "one hundred eleven trillion, one hundred ten billion, one hundred twenty-two million, eleven thousand, twenty".
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