Base | Representation |
---|---|
bin | 10000001010110011111… |
… | …111000000011111011000 |
3 | 10221012222221120022122020 |
4 | 100022303333000133120 |
5 | 121201034011413422 |
6 | 2210235251254440 |
7 | 143163422243256 |
oct | 20126377003730 |
9 | 3835887508566 |
10 | 1111121201112 |
11 | 399250a50a9a |
12 | 15b4142aa420 |
13 | 80a16b5a450 |
14 | 3bac84c75d6 |
15 | 1dd81ed195c |
hex | 102b3fc07d8 |
1111121201112 has 64 divisors (see below), whose sum is σ = 2993089179360. Its totient is φ = 341699558400.
The previous prime is 1111121201063. The next prime is 1111121201153. The reversal of 1111121201112 is 2111021211111.
It is a junction number, because it is equal to n+sod(n) for n = 1111121201091 and 1111121201100.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 376189 + ... + 1537452.
Almost surely, 21111121201112 is an apocalyptic number.
1111121201112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1111121201112 is an abundant number, since it is smaller than the sum of its proper divisors (1881967978248).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1111121201112 is a wasteful number, since it uses less digits than its factorization.
1111121201112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1915524 (or 1915520 counting only the distinct ones).
The product of its (nonzero) digits is 8, while the sum is 15.
Adding to 1111121201112 its reverse (2111021211111), we get a palindrome (3222142412223).
Subtracting 1111121201112 from its reverse (2111021211111), we obtain a palindrome (999900009999).
The spelling of 1111121201112 in words is "one trillion, one hundred eleven billion, one hundred twenty-one million, two hundred one thousand, one hundred twelve".
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