Base | Representation |
---|---|
bin | 10100101100101001… |
… | …11101010100001111 |
3 | 1001200102012122110211 |
4 | 22112110331110033 |
5 | 140224133323043 |
6 | 5034344543251 |
7 | 542236351411 |
oct | 122624752417 |
9 | 31612178424 |
10 | 11112011023 |
11 | 4792493393 |
12 | 21a1481b27 |
13 | 10811b5169 |
14 | 775b0a9b1 |
15 | 450817a9d |
hex | 29653d50f |
11112011023 has 4 divisors (see below), whose sum is σ = 11370429928. Its totient is φ = 10853592120.
The previous prime is 11112010991. The next prime is 11112011041. The reversal of 11112011023 is 32011021111.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11112011023 - 25 = 11112010991 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11112010994 and 11112011012.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11112011083) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 129209388 + ... + 129209473.
It is an arithmetic number, because the mean of its divisors is an integer number (2842607482).
Almost surely, 211112011023 is an apocalyptic number.
11112011023 is a deficient number, since it is larger than the sum of its proper divisors (258418905).
11112011023 is an equidigital number, since it uses as much as digits as its factorization.
11112011023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 258418904.
The product of its (nonzero) digits is 12, while the sum is 13.
Adding to 11112011023 its reverse (32011021111), we get a palindrome (43123032134).
The spelling of 11112011023 in words is "eleven billion, one hundred twelve million, eleven thousand, twenty-three".
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