Base | Representation |
---|---|
bin | 10000001010111111011… |
… | …111000001100011010000 |
3 | 10221020111101121210202101 |
4 | 100022333133001203100 |
5 | 121201432410042230 |
6 | 2210310342530144 |
7 | 143201254234324 |
oct | 20127737014320 |
9 | 3836441553671 |
10 | 1111314143440 |
11 | 39933a953466 |
12 | 15b468a36954 |
13 | 80a47b131c7 |
14 | 3bb05d8d984 |
15 | 1dd93de4aca |
hex | 102bf7c18d0 |
1111314143440 has 80 divisors (see below), whose sum is σ = 2676202462080. Its totient is φ = 428667240960.
The previous prime is 1111314143413. The next prime is 1111314143473. The reversal of 1111314143440 is 443414131111.
It is a tau number, because it is divible by the number of its divisors (80).
It is a junction number, because it is equal to n+sod(n) for n = 1111314143399 and 1111314143408.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1586197 + ... + 2176843.
It is an arithmetic number, because the mean of its divisors is an integer number (33452530776).
Almost surely, 21111314143440 is an apocalyptic number.
1111314143440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1111314143440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1338101231040).
1111314143440 is an abundant number, since it is smaller than the sum of its proper divisors (1564888318640).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1111314143440 is a wasteful number, since it uses less digits than its factorization.
1111314143440 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 591500 (or 591494 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 28.
Adding to 1111314143440 its reverse (443414131111), we get a palindrome (1554728274551).
The spelling of 1111314143440 in words is "one trillion, one hundred eleven billion, three hundred fourteen million, one hundred forty-three thousand, four hundred forty".
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