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111132221311 is a prime number
BaseRepresentation
bin110011101111111111…
…1110001111101111111
3101121211222212210000201
41213133333301331333
53310044322040221
6123015313104331
711012650203136
oct1473777617577
9347758783021
10111132221311
1143149272801
1219655b580a7
13a630c4c947
14554370c91d
152d566e5891
hex19dfff1f7f

111132221311 has 2 divisors, whose sum is σ = 111132221312. Its totient is φ = 111132221310.

The previous prime is 111132221281. The next prime is 111132221383. The reversal of 111132221311 is 113122231111.

It is a m-pointer prime, because the next prime (111132221383) can be obtained adding 111132221311 to its product of digits (72).

It is a weak prime.

It is an emirp because it is prime and its reverse (113122231111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 111132221311 - 233 = 102542286719 is a prime.

It is a super-2 number, since 2×1111322213112 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111132221611) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55566110655 + 55566110656.

It is an arithmetic number, because the mean of its divisors is an integer number (55566110656).

Almost surely, 2111132221311 is an apocalyptic number.

111132221311 is a deficient number, since it is larger than the sum of its proper divisors (1).

111132221311 is an equidigital number, since it uses as much as digits as its factorization.

111132221311 is an evil number, because the sum of its binary digits is even.

The product of its digits is 72, while the sum is 19.

Adding to 111132221311 its reverse (113122231111), we get a palindrome (224254452422).

The spelling of 111132221311 in words is "one hundred eleven billion, one hundred thirty-two million, two hundred twenty-one thousand, three hundred eleven".