Base | Representation |
---|---|
bin | 110100101011010011… |
… | …1000100001101000111 |
3 | 101210222200102202021101 |
4 | 1221112213010031013 |
5 | 3323133242343421 |
6 | 123545002000531 |
7 | 11113163046031 |
oct | 1512647041507 |
9 | 353880382241 |
10 | 113122231111 |
11 | 43a7a6065aa |
12 | 19b104a6147 |
13 | a88a309a36 |
14 | 5691b26c51 |
15 | 2e21283191 |
hex | 1a569c4347 |
113122231111 has 2 divisors, whose sum is σ = 113122231112. Its totient is φ = 113122231110.
The previous prime is 113122231093. The next prime is 113122231129. The reversal of 113122231111 is 111132221311.
It is a balanced prime because it is at equal distance from previous prime (113122231093) and next prime (113122231129).
It is an emirp because it is prime and its reverse (111132221311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113122231111 - 211 = 113122229063 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113122231151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56561115555 + 56561115556.
It is an arithmetic number, because the mean of its divisors is an integer number (56561115556).
Almost surely, 2113122231111 is an apocalyptic number.
113122231111 is a deficient number, since it is larger than the sum of its proper divisors (1).
113122231111 is an equidigital number, since it uses as much as digits as its factorization.
113122231111 is an evil number, because the sum of its binary digits is even.
The product of its digits is 72, while the sum is 19.
Adding to 113122231111 its reverse (111132221311), we get a palindrome (224254452422).
The spelling of 113122231111 in words is "one hundred thirteen billion, one hundred twenty-two million, two hundred thirty-one thousand, one hundred eleven".
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