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1112023100213 is a prime number
BaseRepresentation
bin10000001011101001101…
…111011110101100110101
310221022022210122112121122
4100023221233132230311
5121204410403201323
62210504550153325
7143224653251564
oct20135157365465
93838283575548
101112023100213
11399674060153
1215b626352845
1380b2b96a35c
143bb721b9bdb
151ddd6285ec8
hex102e9bdeb35

1112023100213 has 2 divisors, whose sum is σ = 1112023100214. Its totient is φ = 1112023100212.

The previous prime is 1112023100173. The next prime is 1112023100269. The reversal of 1112023100213 is 3120013202111.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 780957503524 + 331065596689 = 883718^2 + 575383^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1112023100213 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1112023100191 and 1112023100200.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1142023100213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556011550106 + 556011550107.

It is an arithmetic number, because the mean of its divisors is an integer number (556011550107).

Almost surely, 21112023100213 is an apocalyptic number.

It is an amenable number.

1112023100213 is a deficient number, since it is larger than the sum of its proper divisors (1).

1112023100213 is an equidigital number, since it uses as much as digits as its factorization.

1112023100213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 1112023100213 its reverse (3120013202111), we get a palindrome (4232036302324).

The spelling of 1112023100213 in words is "one trillion, one hundred twelve billion, twenty-three million, one hundred thousand, two hundred thirteen".