Base | Representation |
---|---|
bin | 1010000111011001000100… |
… | …0000010101000111001111 |
3 | 1110101021002111012110022012 |
4 | 2201312101000111013033 |
5 | 2424211031344042033 |
6 | 35353231301011435 |
7 | 2225355040414112 |
oct | 241662100250717 |
9 | 43337074173265 |
10 | 11122103112143 |
11 | 35a8948288341 |
12 | 12b76559b3b7b |
13 | 628a6b24897a |
14 | 2a6453d38579 |
15 | 1444a10de248 |
hex | a1d910151cf |
11122103112143 has 2 divisors, whose sum is σ = 11122103112144. Its totient is φ = 11122103112142.
The previous prime is 11122103112137. The next prime is 11122103112149. The reversal of 11122103112143 is 34121130122111.
It is a balanced prime because it is at equal distance from previous prime (11122103112137) and next prime (11122103112149).
It is a cyclic number.
It is not a de Polignac number, because 11122103112143 - 214 = 11122103095759 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11122103112149) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5561051556071 + 5561051556072.
It is an arithmetic number, because the mean of its divisors is an integer number (5561051556072).
Almost surely, 211122103112143 is an apocalyptic number.
11122103112143 is a deficient number, since it is larger than the sum of its proper divisors (1).
11122103112143 is an equidigital number, since it uses as much as digits as its factorization.
11122103112143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 288, while the sum is 23.
Adding to 11122103112143 its reverse (34121130122111), we get a palindrome (45243233234254).
The spelling of 11122103112143 in words is "eleven trillion, one hundred twenty-two billion, one hundred three million, one hundred twelve thousand, one hundred forty-three".
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