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11122451141 is a prime number
BaseRepresentation
bin10100101101111001…
…10010001011000101
31001201010212001121212
422112330302023011
5140234321414031
65035400421205
7542424163154
oct122674621305
931633761555
1011122451141
11479837418a
1221a4a77805
1310833cc149
1477726759b
154516cb12b
hex296f322c5

11122451141 has 2 divisors, whose sum is σ = 11122451142. Its totient is φ = 11122451140.

The previous prime is 11122451107. The next prime is 11122451143. The reversal of 11122451141 is 14115422111.

11122451141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7749280900 + 3373170241 = 88030^2 + 58079^2 .

It is a cyclic number.

It is not a de Polignac number, because 11122451141 - 218 = 11122188997 is a prime.

Together with 11122451143, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11122451143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5561225570 + 5561225571.

It is an arithmetic number, because the mean of its divisors is an integer number (5561225571).

Almost surely, 211122451141 is an apocalyptic number.

It is an amenable number.

11122451141 is a deficient number, since it is larger than the sum of its proper divisors (1).

11122451141 is an equidigital number, since it uses as much as digits as its factorization.

11122451141 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 320, while the sum is 23.

Adding to 11122451141 its reverse (14115422111), we get a palindrome (25237873252).

The spelling of 11122451141 in words is "eleven billion, one hundred twenty-two million, four hundred fifty-one thousand, one hundred forty-one".