Base | Representation |
---|---|
bin | 10100101110000001… |
… | …01000110011010111 |
3 | 1001201012202101100110 |
4 | 22113000220303113 |
5 | 140240101230320 |
6 | 5035434214103 |
7 | 542435601300 |
oct | 122700506327 |
9 | 31635671313 |
10 | 11123461335 |
11 | 47989a4158 |
12 | 21a5284333 |
13 | 1083693bac |
14 | 77744b7a7 |
15 | 45182a5e0 |
hex | 297028cd7 |
11123461335 has 96 divisors (see below), whose sum is σ = 22456792512. Its totient is φ = 4668948480.
The previous prime is 11123461333. The next prime is 11123461361. The reversal of 11123461335 is 53316432111.
It is not a de Polignac number, because 11123461335 - 21 = 11123461333 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11123461331) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 501439 + ... + 523151.
It is an arithmetic number, because the mean of its divisors is an integer number (233924922).
Almost surely, 211123461335 is an apocalyptic number.
11123461335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11123461335 is an abundant number, since it is smaller than the sum of its proper divisors (11333331177).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11123461335 is a wasteful number, since it uses less digits than its factorization.
11123461335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21793 (or 21786 counting only the distinct ones).
The product of its digits is 6480, while the sum is 30.
Adding to 11123461335 its reverse (53316432111), we get a palindrome (64439893446).
The spelling of 11123461335 in words is "eleven billion, one hundred twenty-three million, four hundred sixty-one thousand, three hundred thirty-five".
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